Wednesday, October 2, 2024

mining swimming pools – How does Ocean’s TIDES payout scheme work?

I’m additionally questioning how this truly works since there hasn’t been
any official documentation about it. Nevertheless, given the already accessible data
on the web site, ‘trigger all miners shares and hashrate are public and a few questions
answered on Twitter by @wk057 and @GrassFedBitcoin;
I feel I can have already got a full image of it.

The reward system encompass three important ideas:

  1. shares earn by every consumer,
  2. whole shares on the pool,
  3. and payout primarily based on shares.

The payout is the only factor to elucidate. If a consumer has s shares and the pool
has a complete of total_shares (the sum of all consumer shares) the second a block is discovered, the consumer will get

s * (block_reward) / total_shares

the place block_reward means subsidy plus charges.

The share window Z is the utmost variety of shares the pool will maintain at any time.
When new shares are added older shares are discarded in order that total_shares <= Z.
This quantity is just 8 instances the present tip block problem Z = 8 * network_difficulty.

As soon as the pool is operating for fairly a while the variety of accrued shares
tends to Z, so it’s less complicated to make use of total_shares as Z for calculations
within the examples under.

One share is equal to the work wanted to mine a block with problem 1.
Ocean, like every other pool, challenges the person miners with some problem d
and every time a hash is accepted d shares are added to this miner’s account.

Previous consumer shares are dropped if they’re older than the oldest share within the pool, to maintain
the share window under Z.
That signifies that when a miner begins contributing with a continuing hashrate H,
his share quantity begins rising linearly till a most is reached.
enter image description here

Within the plot, I might name T the leisure time which is in truth the temporal dimension
of the share window, or just the time distinction between the latest and the oldest share
within the pool. I additionally perceive T because the anticipated time for the pool to provide Z shares.
For instance, if the pool has a continuing hashrate H_pool then T is computed as

T = W1 * Z / H_pool

the place W1=0x100010001 is (by the definition of problem 1), the anticipated work wanted
to resolve a problem 1 block.

Additionally within the plot, we see the miner reaches a continuing share quantity <S>_T which is the anticipated
variety of shares this miner will obtain after T seconds of labor.

<S>_T = H * T / W1 = Z * H / H_pool

If a miner with hashrate H reaches the anticipated most variety of shares after which leaves the pool
perpetually, his shares will linearly lower because the oldest shares are thrown away.
enter image description here

Assuming a continuing hashrate of the pool, a share earned at any time will keep legitimate for
time-frame of about T. Now think about the anticipated variety of blocks discovered by the pool
on this time-frame <N>_T:

<N>_T = H_pool * T / W1 / network_difficulty = Z / network_difficulty = 8

therefore the selection of Z = 8 * network_difficulty will also be interpreted as setting the anticipated
variety of payouts for every share to be 8.

A pool has a good incomes distribution if the anticipated incomes(W)
for a certain quantity of labor W
diluted over time is the same as:

incomes(W) = block_reward * W / (W1 * network_difficulty)

assuming a continuing block reward and problem. Within the denominator W1 * network_difficulty
is the anticipated work wanted to mine a block.

Every particular person share earned by a miner within the Ocean pool is obtained after W1 of labor
and it pays out in an anticipated variety of 8 blocks

earning_per_share = 1/Z * 8 * block_reward = block_reward / network_difficulty = incomes(W1)

thus the payout is truthful (in proportion to the work finished) independently of the miner’s
on-line time, hashrate or the pool’s hashrate.

Let the hashrate of the pool be H = 1.25 EH/s, think about Alice a miner with a hashrate
of H_alice = 250 PH/s, which corresponds to a 20% of the pool’s hashrate.
And let network_difficulty = 80T.

The share window of the pool is Z = 8*network_difficulty = 640T and the time window
would correspond to T = Z * W1/H_pool = 330 Ms or about 25 days.

Which signifies that a continuing hashrate and problem, a brand new (small) miner Charlie must wait
for at the very least 25 days till it may possibly attain the utmost variety of shares
it may possibly presumably obtain for his hashrate. Additionally a small miner that leaves the pool
can be paid a fraction of the reward for so long as there may be one in every of his shares nonetheless legitimate,
an anticipated variety of 8 earnings (anticipated variety of blocks discovered by the pool earlier than
all shares on Charlie’s account are thrown away from the window).

Alice has been mining continuous because the begining, so she has already reached the utmost
variety of shares within the window: S_alice = H_alice * T / W1 = 128T.
If a block is discovered, Alice will get S_alice / Z = 20% of the block reward.

Now assume, a giant miner Bob enters the pool with H_bob = 1.25 EH/s, doubling the pool’s
hashrate.
Bob rapidly begins including shares and the pool would wish to discard previous shares
as twice as quick than beforehand to maintain the window dimension at fixed Z. In different phrases
the comfort time T modifications from 25 days to 12 days.
It’ll take Bob 12 days, till he reaches the utmost variety of shares: S_bob = Z/2.
After this second, each time a block is discovered Bob will earch half of the block reward.

If Bob decides to depart perpetually, then his shares will begin lowering linearly with time.
However because the pool has now much less hashrate than when Bob was mining, it should take 25 days earlier than
all of Bob’s shares are gone. However nonetheless the anticipated variety of blocks is 8. Because of the equity argument described above, every one in every of Bob
shares is nearly as good as every other miner shares.

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