For each eventualities that I’ll describe beneath, assume the two issues.
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that community propagation for blocks all the time 6 seconds.
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that we begin taking a look at my evaluation from time = t0 and at that t0, each node has the identical actual chain.
State of affairs 1: block time = 10 min
If block time is 10 min and minerA solves blockD at time t0 + T, and shares it immediatelly, in the course of the time t0+T and t0+T+6, others miners may remedy their very own block that they have been engaged on. Let’s name the variable what number of miners remedy it throughout this time to be “X”
State of affairs 2: block time = 4 min
If block time is 4 min and minerA solves blockD at time t0 + T, and shares it immediatelly, in the course of the time t0+T and t0+T+6, others miners may remedy their very own block that they have been engaged on. Let’s name the variable what number of miners remedy it throughout this time to be “Y”
Because it seems, Y > X.
Query 1: Am I proper that Y could be larger than X ? ofc, not in 100% instances, however when it comes to likelihood.
Query 2: How do I make myself certain that it is mathematically true that Y > X ? I do know it have to be about how difficulties and goal are set. It looks like the much less issue, The upper the prospect to resolve a block throughout ANY 6 second interval. (NOTE the phrase: “ANY”). That is vital as a result of we do not know precisely when minerA solves the block, however as I’ve learn, likelihood that Y > X is true for ANY 6 second interval, and this 6 second interval does not need to be nearer to 4 minutes or 10 minutes or no matter it’s. What could be a mathematical method to this so I consider on this ?
